Given: ABCD is a rectangle in which diagonal AC bisects ∠A as well as ∠C. ∴ Diagonal AC = Diagonal BD. Angle sum property of quadrilaterals and it’s proof Now, the diagonal AC bisects angle C into ∠ ACD and ∠ ACB. Diagonal AC of a parallelogram ABCD bisects A show that it bisects C also, ABCD is a rhombus - Math - Quadrilaterals Given diagonal AC bisects

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